Answer
$$F=39.8 \mathrm{lb}
$$
Work Step by Step
$$
\begin{aligned}
&↺+30\left(\cos 45^{\circ}\right)(18)=F\left(\frac{4}{5}\right)(12)=0\\
&F=39.8 \mathrm{lb}
\end{aligned}
$$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 4 - Force System Resultants - Section 4.4 - Principle of Moments - Problems - Page 139: 16
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