Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 4 - Force System Resultants - Section 4.4 - Principle of Moments - Fundamental Problems - Page 136: 6

Answer

1.06KN.m or 1060.46NM

Work Step by Step

500 Sin45 (3+3cos45) - 500 Cos45 (3 Sin45) =1060.46\approx1060Nm This is a very simple problem, all you need to do is to resolve the distance as well as force into two components, by doing that You will get two perpendicular Distance for Two components of for and Yes one of them is -ve , Why ? ( Clockwise direction), Detailed solution has been attached in pic.
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