Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 3 - Equilibrium of a Particle - Section 3.3 - Coplanar Force Systems - Problems - Page 99: 9



Work Step by Step

We can find the required maximum force as follows: We know that the sum of forces in the y-direction is given as $\Sigma F_y=0$ $\Sigma F_y=-Fsin(30)+T_B(\frac{4}{5})=0$ $\Sigma F_y=-Fsin(30)+(600)(\frac{4}{5})=0$..eq(1) Now the sum of forces in the x-direction is given as $\Sigma F_x=-Fcos(30)+T_B(\frac{3}{5})=0$ $\Sigma F_x=-Fcos(30)+(600)(\frac{3}{5})=0$..eq(2) Solving eq(1) and eq(2), we obtain: $F=960lb$
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