Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 22 - Vibrations - Section 22.6 - Electrical Circuit Analogs - Problems - Page 676: 60



Work Step by Step

We can find the required speed as follows: $\omega_n=\sqrt{\frac{K}{m}}$ $\implies \omega_n=\sqrt{\frac{2\times 800}{450}}$ $\implies \omega_n=1.8856rad/s$ We know that $T=\frac{2\pi}{\omega_n}$ $\implies T=\frac{2\pi}{1.8856}$ $\implies T=3.3322s$ Now $v=\frac{\lambda}{T}$ We plug in the known values to obtain: $v=\frac{4}{3.3322}$ $\implies v=1.2m/s$
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