Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 22 - Vibrations - Section 22.1 - Undamped Free Vibration - Problems - Page 655: 25



Work Step by Step

We can determine the natural frequency of vibration as follows: $\omega_n=\sqrt{\frac{K_{eq}}{m_{eq}}}$ $\implies \omega_n=\sqrt{\frac{3.6}{0.1125}}=4\sqrt{2}rad/s$ Now $f=\frac{\omega_n}{2\pi}$ We plug in the known values to obtain: $f=\frac{4\sqrt{2}}{2\pi}$ $\implies f=0.900Hz$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.