# Chapter 22 - Vibrations - Section 22.1 - Undamped Free Vibration - Problems - Page 655: 25

$f=0.900Hz$

#### Work Step by Step

We can determine the natural frequency of vibration as follows: $\omega_n=\sqrt{\frac{K_{eq}}{m_{eq}}}$ $\implies \omega_n=\sqrt{\frac{3.6}{0.1125}}=4\sqrt{2}rad/s$ Now $f=\frac{\omega_n}{2\pi}$ We plug in the known values to obtain: $f=\frac{4\sqrt{2}}{2\pi}$ $\implies f=0.900Hz$

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