Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 20 - Three-Dimensional Kinematics of a Rigid Body - Section 20.3 - General Motion - Problems - Page 573: 10

Answer

$$ \begin{aligned} & \omega=\{42.4 \mathbf{j}+43.4 \mathbf{k}\} \mathrm{rad} / \mathrm{s} \\ & \boldsymbol{\alpha}=\{-42.4 \mathrm{i}\} \mathrm{rad} / \mathrm{s}^2 \end{aligned} $$

Work Step by Step

$$ \begin{aligned} \omega & =\omega_z+\omega_s \\ & =1 \mathbf{k}+60 \cos 45^{\circ} \mathbf{j}+60 \sin 45^{\circ} \mathbf{k} \\ & =42.426 \mathbf{j}+43.426 \mathbf{k} \\ & =\{42.4 \mathbf{j}+43.4 \mathbf{k}\} \mathrm{rad} / \mathrm{s} \\ \dot{\omega} & =\dot{\omega}_z+\dot{\omega}_s \\ & =0+0+\omega_z \times \omega_s \\ & =1 \mathbf{k} \times 42.426 \mathbf{j}+43.426 \mathbf{k} \\ & =\{-42.4 \mathbf{i}\} \mathrm{rad} / \mathrm{s}^2 \end{aligned} $$
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