Answer
$F_{R} = 4.01 KN$
$\phi = 16.2°$
Work Step by Step
We are asked the sum of two vectores.
Applying the law of cosines:
$F_{R} = \sqrt (2^{2} + 3^{2} - 2 \times 2 \times 3 \times \cos (105°)) = 4.013KN \approx 4.01 KN$
Applying now the law of sines:
$\frac{\sin(\alpha)}{3} = \frac{\sin(105°)}{4.013}$
$\alpha = 46.22°$
Therefore:
$\phi = \alpha - 30° = 16.2°$
