Answer
$$
\begin{aligned}
& s=0.301 \mathrm{~m} \\
& T=163 \mathrm{~N}
\end{aligned}
$$
Work Step by Step
$$
v_A=0.2 \omega=0.2(5)=1 \mathrm{~m} / \mathrm{s}
$$
For System:
$$
\begin{aligned}
& T_1+V_1=T_2+V_2 \\
& {[0+0]+0=\frac{1}{2}(20)(1)^2+\frac{1}{2}\left[50(0.280)^2\right](5)^2-20(9.81) \mathrm{s}} \\
& s=0.30071 \mathrm{~m}=0.301 \mathrm{~m}
\end{aligned}
$$
For Block:
$$
\begin{aligned}
& T_1+\Sigma U_{1-2}=T_2 \\
& 0+20(9.81)(0.30071)-T(0.30071)=\frac{1}{2}(20)(1)^2 \\
& T=163 \mathrm{~N}
\end{aligned}
$$
