Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 18 - Planar Kinetics of a Rigid Body: Work and Energy - Section 18.4 - Principle of Work and Energy - Problems - Page 492: 19

Answer

$$ \omega=6.92 \mathrm{rad} / \mathrm{s} $$

Work Step by Step

$$ \begin{aligned} & T_S+\Sigma U_{1-2}=T_2 \\ & 0+280\left(\theta_A\right)=\frac{1}{2}\left[800(1.75)^2\right] \omega^2 \\ & \theta_S(2)=\theta_A(0.3) \\ & 5(2 \pi)(2)=\theta_A(0.3) \\ & \theta_A=209.4 \mathrm{rad} \end{aligned} $$ Thus $$ \omega=6.92 \mathrm{rad} / \mathrm{s} $$
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