Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 16 - Planar Kinematics of a Rigid Body - Section 16.4 - Absolute Motion Analysis - Problems - Page 343: 47


$v=-r\omega \sin\theta$

Work Step by Step

We can determine the required velocity as follows: $x=r+rcos\theta$ Differentiating with respect to time, we obtain: $\frac{dx}{dt}=-rsin\theta\frac{d\theta}{dt}~~~$[eq(1)] We know that $\omega=\frac{d\theta}{dt}$ and $v=\frac{dx}{dt}$ Thus eq(1) becomes $v=-r\omega \sin \theta$
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