## Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson

# Chapter 16 - Planar Kinematics of a Rigid Body - Section 16.3 - Rotation about a Fixed Axis - Problems - Page 335: 29

#### Answer

$r_A=31.8~mm$ $r_B=31.8~mm$ $n=1.90~canisters/min$

#### Work Step by Step

We can determine the required radius and the number of canisters as follows: As $l=2\pi r_A$ $\implies 200=2\pi r_A$ This can be rearranged as: $r_A=\frac{200}{2\pi}=31.8309mm$ Similarly, $r_B=\frac{200}{2\pi}$ $\implies r_B=31.8309mm$ Now the number of the canisters can be calculated as $n=\frac{l}{200}$ $\implies n=\frac{\theta_B r_B}{200}$ We plug in the known values to obtain: $n=\frac{12\times 31.8909}{200}$ $\implies n=1.90~canisters/min$

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