Answer
$\theta=3.32rev$
$t=1.67s$
Work Step by Step
We can determine the required number of revolutions and the time as follows:
$\omega^2=\omega_{\circ}^2+2\alpha(\theta-\theta_{\circ})$
We plug in the known values to obtain:
$(15)^2=(10)^2+2(3)(\theta-0)$
This simplifies to:
$\theta=(20.83)(\frac{1rev}{2\pi rad})=3.32rev$
Now $\omega=\omega_{\circ}+\alpha t$
We plug in the known values to obtain:
$15=10+3t$
This simplifies to:
$t=1.67s$
