Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.7 - Principle of Angular Impulse and Momentum - Problems - Page 293: 107



Work Step by Step

We can determine the required speed as follows: According to the principle of angular impulse and momentum $\Sigma H_{z_1}+\Sigma \int_{t_1}^{t_2}M_z dt=H_{z2}$ We plug in the known values to obtain: $0+\int_0^5 30t^dt+in_0^5 15t(4)dt=150v(4)$ This simplifies to: $v=3.33m/s$
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