Answer
$v=9.50m/s$
Work Step by Step
We can determine the required speed as follows:
According to the principle of impulse and momentum
$2rmv_1+M(t_2-t_1)=2rmv_2$
We plug in the known values to obtain:
$2(0.3)(0.4)(2)+(3)(0.6)=2(0.3)(0.4)v_2$
This simplifies to:
$v_2=9.50m/s$
