Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.7 - Principle of Angular Impulse and Momentum - Problems - Page 292: 105



Work Step by Step

We can determine the required speed as follows: According to the principle of impulse and momentum $2rmv_1+M(t_2-t_1)=2rmv_2$ We plug in the known values to obtain: $2(0.3)(0.4)(2)+(3)(0.6)=2(0.3)(0.4)v_2$ This simplifies to: $v_2=9.50m/s$
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