Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.2 - Principle of Linear Impulse and Momentum for a System of Particles - Problems - Page 252: 27

Answer

$5.07m/s$

Work Step by Step

The speed of the crate can be determined as follows: $mv_{y_1}+\Sigma \int ^{t_2}_{t_1} F_y dt=mv_{y_2}$ We plug in the known values to obtain: $10+2\int ^{3}_{0} (100+5t^2)dt-20(9.81)(3)=20v$ $\implies 2(100t+\frac{5}{3}t^3)|^3_{0}-588.6=20v$ This simplifies to: $v=5.07m/s$
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