Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.2 - Principle of Linear Impulse and Momentum for a System of Particles - Problems - Page 251: 20



Work Step by Step

According to impulse momentum principle $mv_1+\Sigma \int ^{t_2}_{t_1}F_xdt=mv_2$ We plug in the known values to obtain: $\frac{200}{32.2}+\int ^5_{0} 20(t+1) cos 30^{\circ} dt=(\frac{200}{32.2})v$ $\implies -124.22+20 cos 30^{\circ} (0.5t^2+t)|^5_{0}=6.211v$ This simplifies to: $v=28.8ft/s$
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