Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.2 - Principle of Linear Impulse and Momentum for a System of Particles - Problems - Page 249: 11



Work Step by Step

We can determine the required speed as follows: We apply the principle of impulse and momentum in the $y$-direction: $mv_{y_1}+\Sigma \int_{t_1}^{t_2}F_ydt=mv_{y_2}$ We plug in the known values to obtain: $2(-90)+\frac{1}{2}(0.4\times 10^{-3})(500\times 10^3)=2v$ This simplifies to: $v=60m/s$
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