## Engineering Mechanics: Statics & Dynamics (14th Edition)

$I=5.68N\cdot s$
We can determine the magnitude of the required net impulse as follows: According to the impulse momentum principle in the vertical direction $mv_1+I_y=mv_2$ We plug in the known values to obtain: $0.2\times 0+I_y=(0.2\times 20sin40)$ This simplifies to: $I_y=2.5711N$ Now we apply the impulse momentum principle in the horizontal direction $mv_1+I_x=mv_2$ We plug in the known values to obtain: $0.2\times (-10)+I_x=0.2\times 20cos40$ $\implies I_x=5.06417N\cdot s$ Now $I=\sqrt{I_x^2+I_y^2}$ We plug in the known values to obtian: $I=\sqrt{(2.5711)^2+(5.06417)^2}$ $\implies I=5.68N\cdot s$