## Engineering Mechanics: Statics & Dynamics (14th Edition)

$F=367.3N$
The required force can be determined as follows: $\Sigma U_{A\rightarrow B}=F(AC-BC)$ $\Sigma U_{A\rightarrow B}=F(\sqrt{(8)^2+(6)^2})=F(3.675)$ Now according to the principle of work and energy $\frac{1}{2}+\Sigma U_{A\rightarrow B}=\frac{1}{2}mv_B^2$ We plug in the known values to obtain: $0+F(3.675)=\frac{1}{2}(75)(6)^2$ This simplifies to: $F=367.3N$