Answer
$7.47~km/s$
Work Step by Step
We can determine the required speed as follows:
$v_p=v_A=\sqrt{\frac{2GMr_a}{r_p(r_p+r_a)}}$
We plug in the known values to obtain:
$v_A=\sqrt{\frac{2\times 66.73(10^{-12})\times 0.7\times 5.976\times 10^{24}}{6\times 10^6(6\times 10^6+9\times 10^6)}}$
This simplifies to:
$v_A=7471.89m/s=7.47~km/s$