Answer
$v=22.1$ m/s
Work Step by Step
$\Sigma F_n = ma_n$
$N=250(\frac{v^2}{20})$
$\Sigma F_b = ma_b$
$0.4 N - 250(9.81)=0$
Solving,
$N=6131.25$ N
$v=22.1$ m/s
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 13 - Kinetics of a Particle: Force and Acceleration - Section 13.5 - Equations of Motion: Normal and Tangential Coordinates - Problems - Page 148: 66
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
