Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 13 - Kinetics of a Particle: Force and Acceleration - Section 13.5 - Equations of Motion: Normal and Tangential Coordinates - Problems - Page 146: 52



Work Step by Step

The required speed can be determined as follows: $F_n=m\frac{mv^2}{r}$ $\implies \mu N=m\frac{v^2}{r}$ $\implies \mu mg=m\frac{v^2}{r}$ This can be rearranged as: $v=\sqrt{\mu g r}$ We plug in the known values to obtain: $v=\sqrt{(0.2)(9.81)(5)}$ This simplifies to: $v=3.13m/s$
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