Answer
$t=2.11s$
Work Step by Step
The required time can be determined as follows:
$\Sigma F_y=-mgsin60+F_N=0$
$\implies F_N=mgsin60$
and, $F_x=-mgcos60+F_f=ma_x$
$-mgcos60+mgsin60(\mu_s)=ma_x$
$\implies g(\mu_s sin60-cos60)=a_x$
This simplifies to:
$a_x=1.89156m/s^2$
Now, $v_x=1.89156(t)-4m/s$
This simplifies to:
$t=2.11s$