Answer
$a_r=-6.67$ m/s$^2$
$a_\theta=3$ m/s$^2$
Work Step by Step
$r=60$
$a_t=3$ m/s$^2$
$a_n=\frac{v^2}{r}=\frac{20^2}{60}=6.67$ m/s$^2$
$a_r=-a_n=-6.67$ m/s$^2$
$a_\theta=a_t=3$ m/s$^2$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.8 - Curvilinear Motion: Cylindrical Components - Problems - Page 83: 184
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
