Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.3 - Rectilinear Kinematics: Erratic Motion - Problems - Page 30: 48

Answer

$a_{max}=4.00$ m/s$^2$

Work Step by Step

For $0 \leq t < 4$ s $a=\frac{\Delta v}{\Delta t}=\frac{14}{4}=3.5 m/s^2$ For $4 \leq t < 5$ s $a=\frac{\Delta v}{\Delta t}=0 m/s^2$ For $5 \leq t < 8$ s $a=\frac{\Delta v}{\Delta t}=\frac{26-14}{8-5}=4 m/s^2$ $a_{max}=4.00 m/s^2$
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