Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 11 - Virtual Work - Section 11.3 - Principle of Virtual Work for a System of Connected Rigid Bodies - Problems - Page 596: 24



Work Step by Step

We can determine the required position $x$ as follows: The virtual displacements are given as $\delta_{yF}=\frac{d(2cos\theta)}{d\theta}=2sin\theta$ and $\delta_{yG}=\frac{d(4+xcos\theta)}{d\theta}=(4+x)sin\theta$ Now, according to the virtual-work equation $\delta U=0$ $\implies F\delta_{yF}+G\delta_{yG}=0$ We plug in the known values to obtain: $20(2)sin\theta-2(4+x)sin\theta=0$ This simplifies to: $x=16in$
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