Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 10 - Moments of Inertia - Section 10.7 - Mohr's Circle for M oments of Inertia - Problems - Page 560: 66


$I_{xy}=98.4\times (10^6)mm^4$

Work Step by Step

We can find the product of inertia of the cross-sectional area with respect to the x and y axes as follows: $I_{xy}=\Sigma I_{xy}$ We plug in the known values to obtain: $I_{xy}=49.2\times 10^6+0+49.2\times 10^6$ This simplifies to: $I_{xy}=98.4\times (10^6)mm^4$
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