Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 10 - Moments of Inertia - Section 10.4 - Moments of Inertia for Composite Areas - Problems - Page 544: 27


$A=14\cdot (10^3)~mm^2$

Work Step by Step

We can determine the required area as follows: $A=\frac{I_x+I_y-J_c}{d^2y}$ We plug in the known values to obtain: $A=\frac{938\cdot 10^6mm^4+264\cdot 10^6mm^4-642\cdot mm^4}{(200)^2mm^2}$ This simplifies to: $A=14\cdot (10^3)~mm^2$
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