Answer
$A=14\cdot (10^3)~mm^2$
Work Step by Step
We can determine the required area as follows:
$A=\frac{I_x+I_y-J_c}{d^2y}$
We plug in the known values to obtain:
$A=\frac{938\cdot 10^6mm^4+264\cdot 10^6mm^4-642\cdot mm^4}{(200)^2mm^2}$
This simplifies to:
$A=14\cdot (10^3)~mm^2$
