Engineering Mechanics: Statics & Dynamics (14th Edition)

$I_x=204.8in^4$
The required moment of inertia can be determined as follows: $dA=xdy$ Given that $y^2=x$ $\implies dA=y^2 dy$ Now $I_x=\int y^2 dA$ $\implies I_x=\int _0^4 y^2 y^2 dy$ $\implies I_x=\int_0^4 y^4dy$ $\implies I_x=\frac{y^5}{5}|_0^4$ $\implies I_x=\frac{1024}{5}$ $\implies I_x=204.8in^4$