Answer
element A absorbs power and has $P_A=-20\ W$
element B absorbs power and has $P_B=12\ W$
element C absorbs power and has $P_C=-4\ W$
element D absorbs power and has $P_D=12\ W$
Total delivered power $=24\ W$
Total absorbed power $=-24\ W$
Work Step by Step
- Assuming the directions/polarities are correct, an element absorbs power if current enters the positive pole of the voltage, and delivers power if current leaves the positive pole of the voltage
For element A:
current enters the positive pole of voltage; thus, power is absorbed
$P_A=-4\times 5=-20\ W$
For element B:
current leaves the positive pole of voltage; thus, power is delivered
$P_B=6\times 2=12\ W$
For element C:
current enters the positive pole of voltage; thus, power is absorbed
$P_C=-2\times 2=-4\ W$
For element D:
current leaves the positive pole of voltage; thus, power is delivered
$P_D=4\times 3=12\ W$
Total delivered power$ = P_B+P_D=12+12=24\ W$
Total absorbed power$ = P_A+P_C=-20-4=-24\ W$
