## Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall

# Chapter 1 - Practice Test - Practice Test - Page 44: T1.4

#### Answer

$a) \ V_1 = 8V \\ b) \ I = 2A \\ c) \ R_2 = 2\Omega$

#### Work Step by Step

a) We use Kirchhoff's Voltage Law, which states that the voltage around any closed loop in a circuit is 0, to find: $4 -12 + V_1 = 0 \\ V_1 - 8 = 0 \\ V_1 = \fbox{8V}$ b) We apply Ohm's law, which states that $I=\frac{V}{R}$, to find: $I = \frac{8V}{4\Omega} = \fbox{2A}$ c) We use Ohm's law to find: $I=\frac{V}{R} \\ R=\frac{V}{I} \\ R = \frac{4V}{2A} = 2 \Omega$

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