Chapter 8 - 8.3 - Encryption - Practice Problem - Page 419: 1

In the example, where $n=21$ and $e=5,$ then $d=5$ as well. To decode, compute $C^{d}=17^{5}=1419857=67612 \times 21+5 \rightarrow 5$ Therefore the original numeric message was $5$ .

In the example, where $n=21$ and $e=5,$ then $d=5$ as well. To decode, compute $C^{d}=17^{5}=1419857=67612 \times 21+5 \rightarrow 5$ Therefore the original numeric message was $5$ .