## Invitation to Computer Science 8th Edition

The truth table is already given, and again there is only one case with a 1 bit in the output. This occurs in the first row and corresponds to the Boolean expression $\overline{a} \cdot \overline{b}$ Given this single subexpression, we can proceed immediately to draw the circuit diagram: $$continue\ solution\ by\ see\ the\ following\ image:$$
The truth table is already given, and again there is only one case with a 1 bit in the output. This occurs in the first row and corresponds to the Boolean expression $\overline{a} \cdot \overline{b}$ Given this single subexpression, we can proceed immediately to draw the circuit diagram: