Answer
For a list of 3 items, we have $3 !=6$ permutations, as follows:
$\begin{array}{ll}
{[4,3,7]} & {(1)} \\
{[4,7,3]} & {(2)} \\
{[7,3,4]} & {(3)} \\
{[7,4,3]} & {(4)} \\
{[3,4,7]} & {(5)} \\
{[3,7,4]} & {(6)}
\end{array}$
Work Step by Step
For a list of 3 items, we have $3 !=6$ permutations, as follows:
$\begin{array}{ll}
{[4,3,7]} & {(1)} \\
{[4,7,3]} & {(2)} \\
{[7,3,4]} & {(3)} \\
{[7,4,3]} & {(4)} \\
{[3,4,7]} & {(5)} \\
{[3,7,4]} & {(6)}
\end{array}$
