# Chapter 3 - 3.3 - Measuring Efficiency - Practice Problems - Page 109: 2

This question can be answered using the formulas from Section $3.3 .3 :$ Number of comparisons $=\frac{1}{2} n^{2}-\frac{1}{2} n$ $\ \ \ \ \ \$ Number of exchanges $=n$ $\begin{array}{lll}{\text { a. Comparisons: }} & {6} & {\text { Exchanges: }} & {4} \\ {\text { b. Comparisons: }} & {21} & {\text { Exchanges: }} & {7} \\ {\text { c. Comparisons: }} & {28} & {\text { Exchanges: }} & {8} \\ {\text { d. Comparisons: }} & {10} & {\text { Exchanges: }} & {5}\end{array}$

#### Work Step by Step

This question can be answered using the formulas from Section $3.3 .3 :$ Number of comparisons $=\frac{1}{2} n^{2}-\frac{1}{2} n$ $\ \ \ \ \ \$ Number of exchanges $=n$ $\begin{array}{lll}{\text { a. Comparisons: }} & {6} & {\text { Exchanges: }} & {4} \\ {\text { b. Comparisons: }} & {21} & {\text { Exchanges: }} & {7} \\ {\text { c. Comparisons: }} & {28} & {\text { Exchanges: }} & {8} \\ {\text { d. Comparisons: }} & {10} & {\text { Exchanges: }} & {5}\end{array}$

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