Answer
Yes, it would still work correctly in one sense—it would find the largest numerical value in the list. However, if two numbers were equal, this change would cause the algorithm to find the last occurrence of that number rather than the first. So the value of the largest so far would not change but the value of location might be different.
Work Step by Step
Yes, it would still work correctly in one sense—it would find the largest numerical value in the list. However, if two numbers were equal, this change would cause the algorithm to find the last occurrence of that number rather than the first. So the value of the largest so far would not change but the value of location might be different.
