## Invitation to Computer Science 8th Edition

Yes, the algorithm still works correctly. On Line 1, we input the two values a = 0, b = 0. On Line 2, the Boolean expression is true, so we set product = 0 and skip the entire else clause. The next line executed is “print the value of product” which outputs a = 0, the correct answer to the problem 0 $\times$ 0.
Yes, the algorithm still works correctly. On Line 1, we input the two values a = 0, b = 0. On Line 2, the Boolean expression is true, so we set product = 0 and skip the entire else clause. The next line executed is “print the value of product” which outputs a = 0, the correct answer to the problem 0 $\times$ 0.