Answer
The output of the given program will be:
4
0
Work Step by Step
The value of i is initialized as 3 by the super()._ _init_ _(3) and then the m1 function is called which adds 1 to i, so the value of i becomes 4 which is printed in the first line. The value of j is initialized as 0 and remains unchanged so 0 is printed in the second line.
