Answer
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Work Step by Step
Yes, the given Bare Bones program is self-terminating. It decrements the value of variable \( \mathbf{X} \) until it becomes zero, and once \( \mathbf{X} \) reaches zero, the loop condition becomes false, terminating the program. Therefore, the program will terminate on its own without needing any external intervention assuming \( \mathbf{X} \) starts with a non-negative integer value.
