Answer
The current that passes through a meter of axon is $ I = 8.96\times10^{-6} A$
Work Step by Step
$Q = Ne$
$Q = (5.6\times10^{-11})(|-1.6\times10^{-19}|C)$
$Q = 8.96\times10^{-8}C$. This represents the amount of charge passing through 1 meter of the axon.
Therefore, the current passing through is:
$I=\frac{Q}{t}$
$I = \frac{8.96\times10^{-8}C}{10\times10^{-3}s}$
$ I = 8.96\times10^{-6} A$
