University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 25 - Current, Resistance, and Electromotive Force - Problems - Exercises - Page 842: 25.20

Answer

The resistivity is $=13.8\times10^{-8}Ωm$

Work Step by Step

$A = π\times r^{2}$ $A = π\times (0.00654m)^{2}$ $Area = 1.344\times10^{-6}m^{2}$. From Ohm's Law, the resistance is given by: $R = \frac{Voltage}{Current}$ Therefore, the resistance is $R = \frac{4.50 V}{17.6 A} = 0.256 Ω$. The formula for resistivity is : ρ $ = \frac{ RA}{L}$ Therefore, the resitivity is $$ρ = \frac{ 1.344\times10^{-6}m^{2}\times0.256Ω}{2.50 m }$$ $$=13.8\times10^{-8}Ωm$$
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