Answer
The resistance is $R = 0.125 Ω$,
Work Step by Step
$A = \frac{π}{4}\times d^{2}$
$A = \frac{π}{4}\times (2.05\times10^{-3}m)^{2}$
$A = (3.3\times10^{-6}m^{2}$). This area represents the cross sectional area of the wire.
The resistivity of a wire for copper is found from Table 25.1 and it is therefore,
$ρ = 1.72\times10^{-8} Ωm$
The formula for resistance is : $R=\frac{ρL}{A}$
$$R = \frac{1.72\times10^{-8} Ωm\times24m}{3.3\times10^{-6}m^{2}}$$
$$R = 0.125 Ω$$
