Answer
$\Delta S = 10.0 J/K$
Work Step by Step
$\Delta S = nR ln \frac{V_2}{V_1}$
$\Delta S = (0.100 mol)(8.314 J/mol.K) ln (\frac{425 m^3}{2.40 \times 10^{-3} m^3})$
$\Delta S = 10.0 J/K$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 20 - The Second Law of Thermodynamics - Problems - Exercises - Page 678: 20.31
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