Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 214: 79

Answer

(a) $15h$ (b) $0.62\frac{m}{s}$ (c) $1.6s$

Work Step by Step

(a) We know that $P=\frac{W}{t}$ This can be rearranged as: $t=\frac{W}{P}$ We plug in the known values to obtain: $t=\frac{280Cal\times 4186J/Cal}{22W}$ $t=53,300\times \frac{1h}{3600s}$ $t=15h$ (b) As $P=Fv$ This can be rearranged as: $v=\frac{P}{F}$ $v=\frac{P}{mg}$ We plug in the known values to obtain: $v=\frac{22}{(3.6)(9.81)}$ $v=0.62\frac{m}{s}$ (c) We can find the required time as $v=\frac{d}{t}$ $\implies t=\frac{d}{v}$ We plug in the known values to obtain: $t=\frac{1.0}{0.62}$ $t=1.6s$
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