Answer
(a) $2.0m/s^2$
(b) decrease
(c) $1.0m/s^2$
Work Step by Step
(a) We can find the required acceleration as follows:
$a=\frac{F}{m}$
$\implies a=\frac{P/v}{m}$
We plug in the known values to obtain:
$a=\frac{(49hp\times 746W/hp)}{(1300)(14)}$
$a=2.0m/s^2$
(b) We know that $\implies a=\frac{P/v}{m}$. This equation shows that if the speed of the car is doubled then the acceleration will decrease.
(c) We can find the required acceleration as follows:
$a=\frac{F}{m}$
$\implies a=\frac{P/v}{m}$
We plug in the known values to obtain:
$a=\frac{(49hp\times 746W/hp)}{(1300)(28)}$
$a=1.0m/s^2$
