Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 214: 74

Answer

$W=3.7\times 10^{-4}W$

Work Step by Step

To find the power, use the formula for power $$P=Fvcos\theta$$ In this case, $F=mg$. This leaves $$P=mgvcos\theta$$ Substituting known values of $m=1.8g =0.0018kg$, $v=2.3cm/s=0.023m/s$, and $\theta=25^{\circ}$ yields a power of $$P=(0.0018kg)(9.8m/s^2)(0.023m/s)cos(25^{\circ})=3.7\times 10^{-4}W$$
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