Answer
(a) $13.1J$
(b) $13.1J$
(c) stay the same
Work Step by Step
(a) We can find the work done as follows:
$W=Fd$
We plug in the known values to obtain:
$W=(2.89)(4.55)$
$W=13.1J$
(b) We can see that the horizontal or parallel component of the force does not change. Hence, the same amount of work is done as in part (a) -- that is, $13.1J$
(c) We know that the work done in part (a) and (b) will stay the same even if the mass is increased because the work done is independent of the mass.
