Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1043: 55

Answer

$0.19nJ$

Work Step by Step

We can find the required work done as follows: $W=K.E_f-K.E_i$ We plug in the known values to obtain: $W=(\frac{m_{\circ}c^2}{\sqrt{1-v^2/c^2}}-m_{\circ}c^2)-0$ $\implies W=m_{\circ}c^2(\frac{1}{\sqrt{1-v^2/c^2}}-1)$ We plug in the known values to obtain: $W=1.673\times 10^{-27}(3.00\times 10^8)(\frac{1}{\sqrt{1-(0.90)^2}}-1)$ $W=0.19nJ$
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