Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1043: 58

Answer

$75J$

Work Step by Step

We can find the required energy as $E=\Delta mc^2$ We plug in the known values to obtain: $E=(8.3\times 10^{-16})(3.00\times 10^8)^2$ $E=75J$
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