Answer
$0.53c$
Work Step by Step
We can determine the required relative speed as follows:
$v_2=\frac{v-v_1}{1-\frac{vv_1}{c^2}}$
We plug in the known values to obtain:
$v_2=\frac{0.77c-0.41c}{1-\frac{(0.77c)(0.41c)}{c^2}}$
$v_2=0.53c$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1042: 42
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